- Let f(x) = sin x. Find the first 3 derivatives of f.
- Let f(t) = 5 cos t. Find the first 4 derivatives of f.
- Let f(x) = 3cos x + 5x. Find the first 3 derivatives of f.
- Let f(t) = 2t + sin t. Find the first 3 derivatives of f.
- Let f(t) = 1/t2 - sin t. Find the first 2 derivatives of f.
- Let f(x) = sin x - cos x. Find the first 4 derivatives of f.
- Let f(x) = 2sin x + 3cos x. Find the first 4 derivatives of f.
- Let f(x) = 4sin x + 1/x. Find the first 3 derivatives of f.
- Let f(t) = -3sin t + 1/2 cos t. Find the first 3 derivatives of f.
Saturday, March 21, 2009
Question set 5
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(1) let y= sin x
ReplyDeletedy/dx= cos x
d^2y/dx^2= - sinx
d^3y/dx^3= -cos x
(2)let y=5 cos t
dy/dx= 5 -sin t
d^2y/dx^2= 5 -cos t
d^3y/dx^3= 5 sin t
d^4y/dx^4= 5 cos t
no 3
ReplyDeletey = 3 cos x + 5x
dy/dx = 3 -sin x + 5
d^2y/dx^2 = 3 -cos x
d^3y/dx^3 = 3 sin x
no 4
ReplyDeletey = 2t + sint
dy/dt = 2 + cost
d^2y/dx^2 = -sint
no 5
ReplyDeletey = 1/t^2 - sint
y = t^-2 - sint
dy/dt = -2t^-3 - cost
d^2y/d^2t = 6t^-4 + sint
NO.6
ReplyDeleteLet f(x) = sin x - cos x. Find the first 4 derivatives of f.
would let f(x) = y
rewrite
y = sin x - cos x
dy/dx of sin x = cos x and dy/dx of cos x = -sin x
so dy/dx = cos x + sin x
d^2y/dx^2 = -sin x + cos x
d^3y/dx^3 = -cos x - sin x
d^4y/dx^4 = sinx - cos x
1)Let f(x) = sin x. Find the first 3 derivatives of f.
ReplyDeletelet y= sin x
First derivative...........dy/dx= cos x
Second derivative..........d^2y/dx^2= - sinx
Third derivative...........d^3y/dx^3= -cos x
2)Let f(t) = 5 cos t. Find the first 4 derivatives of f.
let y=5 cos t
First Derivative...........dy/dx= 5 -sin t
Second derivative..........d^2y/dx^2= 5 -cos t
Third derivative...........d^3y/dx^3= 5 sin t
Forth derivative...........d^4y/dx^4= 5 cos t
3)Let f(x) = 3cos x + 5x. Find the first 3 derivatives of f.
y = 3cos x + 5x
First derivative...........dy/dx = 3 -sin x + 5
Second derivative..........d^2y/dx^2 = 3 -cos x
Third derivative...........d^3y/dx^3 = 3 sin x
9)Let f(t) = -3sin t + 1/2 cos t. Find the first 3 derivatives of f.
....First derivative
dy/dx = 3 -cos t - 1/2 sin t
....Second derivative
d^2y/dx^2 = 3 sin t + 1/2 cos t
....Third derivatived
d^3y/dx^3 = 3 cos t + 1/2 -sin t
question 8
ReplyDeletef(x) = 4sinx + 1/x
f(x) = 4sinx + x^-1
1st derivative
dy/dx = 4cosx - x^-2
2nd derivative
d^2y/dx^2 = -4sinx + 2x^-3
3rd derivative
d^2y/dx^2 = -4cosx -6x^-4