Tuesday, April 7, 2009

Matrices

  1. ....... is used to represent space in the matrix

14 ................6

5x-3 ............8

What value of x will this matrix be singular?

  1. What values of p will make this matrix singular

6p + 2 .........8

5 ...................3p

  1. Can a singular matrix have an inverse, justify your answer?
  2. Tom bought 6 plums and 5 mangoes for $40. Jane bought 3 similar plums and 4 similar mangoes for $23. Using the matrix method determine the price of 1 plum and the price of 1 mango.

25 comments:

  1. This comment has been removed by the author.

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  2. What values of p will make this matrix singular
    6p + 2 .........8
    5 ..............3p

    The same method above implies for this question.

    Someone else give it a try.

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  3. Question 1
    14 ..............6
    5x-3 ............8
    What value of x will this matrix be singular?

    So we all know that when a matrix is singular the determinant is = 0. And to find the determinant it the Major - Minor

    So
    Major - Minor = 0

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  4. for the question above i completed is as:

    14 * 8 = 112............major

    since the major and minor must be cancelled off to make 0

    I then divided 112 by 6
    In other words, this is the value in which 5x - 3 such be multiplied by.

    112/ 6 = 18.67

    Now the equation is formed

    5x - 3 = 18.67
    5x = 21.67
    x = 21.67/3
    x = 4.33

    Now i work it back out to see if am correct
    Major - Minor = 0
    14 x 8 - 6 x 5x-3 = 0

    Substitute the value of x
    14 x 8 - 6 x 5(4.33)-3 = 0
    112 - 111.9 = 0.1
    0.1 to the nearst value = 0

    thats the closed i got

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  5. For question 2, am getting a lot of problems in thoses types of questions,, can someone show me how its done using step for step so i can try some....

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  6. I don't think a singular matrix has an inverse since it is already in forms of ones and zeroes.

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  7. i will give it a try ok 'SWANKY THING"

    6p + 5m = 40 ( TOm )
    3p + 4m = 23 ( Jane)

    putting it into matrix form

    A B C
    (6 5) (p) = (40)
    (3 4) (m) (23)

    *hope u understand that i tried the best i can

    find inverse = 1/determinate X (4 -5)
    (-3 6)

    move around the major and negate the minor
    determinate = major - minor
    = ( 4 X 6) - (5 X 3)
    = 24 - 15
    = 9

    then multiple both sides by the inverse
    and any matrix X the inverse always = 1

    therefore matrix A X inverse = (1 0)
    (0 1)

    then u end up with

    (1 0) X (p) = 1/9 (4 -5) X (40)
    (0 1) (m) (-3 6) (23)


    it works out to be

    (p) = 1/9 (45)
    (m) (18)

    p = 5
    m = 2

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  8. to summarize

    STEPS :

    1) Write in matrix form
    2) Find inverse with determinate
    3) Multiple both sides by inverse which then evaluates the answers

    * do u understand now ??

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  9. Question 1
    14 (6)
    5x-3 (8)
    What value of x will this matrix be singular?

    So we all know that when a matrix is singular the determinant is = 0. And to find the determinant it the (Major - Minor)

    Therefore:
    Major - Minor = 0

    ReplyDelete
  10. 6p + 5m = 40 ( TOm )
    3p + 4m = 23 ( Jane)

    putting it into matrix form

    A B C
    (6 5) (p) = (40)
    (3 4) (m) (23)

    *hope u understand that i tried the best i can

    find inverse = 1/determinate X (4 -5)
    (-3 6)

    move around the major and negate the minor
    determinate = major - minor
    = ( 4 X 6) - (5 X 3)
    = 24 - 15
    = 9

    then multiple both sides by the inverse
    and any matrix X the inverse always = 1

    therefore matrix A X inverse = (1 0)
    (0 1)

    then u end up with

    (1 0) X (p) = 1/9 (4 -5) X (40)
    (0 1) (m) (-3 6) (23)


    it works out to be

    (p) = 1/9 (45)
    (m) (18)

    p = 5
    m = 2

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  11. Yea i believe so....Have to practice doh

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  12. (6 5) (x) (40)
    (3 4) (y) (23)

    6x + 5y = 40
    3x + 4y = 23

    Matrix multiply by inverse = identity

    (1 0)
    (0 1)

    determinant is obtained from subtracting the minor from the major.

    (6 x 4) - (5 x 3)
    24 - 15
    9

    1/9 (4 -5)
    (-3 6)

    1/9 (6 5) (4 -5)
    (3 4) (-3 6)

    (6 x 4 + 5 x -3 6 x -5 + 5 x 6)
    (3 x 4 + 4 x -3 3 x -5 + 4 x 6)

    ( 24 - 15 -30 + 30)
    ( 12 - 12 -15 + 24)

    1/9 (9 0)
    (0 9)

    (1 0)
    (0 1)

    (1 0) (x) = 1/9 (4 -5) (40)
    (0 1) (y) (-3 6) (23)

    (x) = (4 -5) (40)
    (y) (-3 6) (23)

    1/9 ( 4 x 40 -5 x 23)
    (-3 x 40 6 x 23)

    1/9 ( 160 -115)
    (-120 + 138)

    1/9 (45)
    (18)

    (5)
    (2)

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  13. For the following question I read swanky things solution and she me reason to agree with her solution.

    14 ..............6
    5x-3 ............8

    Someone else may prove us wrong.

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  14. 14.............6
    5x-3...........8

    to work out a ques like this you first have to know what is a singualr matrix, then what is the major and what is the minor.

    then you get 14*8 - major
    6(5x-3)- minor then yo can find x

    5x-3*6= 0

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  15. 6p + 5m = 40 ( Tom)
    3p + 4m = 23 ( Jane)

    matrix form

    (6 5) (p) = (40)
    (3 4) (m) (23)

    determinant= ad-bc
    6*4 - 5*3 = 9

    inverse= 1/det * (d -b)
    (-c a)


    same as ( 4 -5)
    (-3 6)

    therefore the inverse = 1/9 * ( 4 -5)
    (-3 6)

    then u multiply the matrix * inverse

    1/9 * ( 4 -5) * (6 5)
    (-3 6) (3 4)


    then u work it out and ul find p and m

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  16. ok johnsmith i'll try it your way

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  17. 6p + 5m = 40 ( TOm )
    3p + 4m = 23 ( Jane)
    1) Write in matrix form
    A B C
    (6 5) (p) = (40)
    (3 4) (m) (23)

    2) Find inverse with determinate
    = 1/determinate X (4 -5)
    (-3 6)
    minor determinate = major - minor
    = ( 4 X 6) - (5 X 3)
    = 24 - 15
    = 9

    3) Multiple both sides by inverse which then evaluates the answers
    matrix A X inverse = (1 0)(0 1)
    so (1 0) X (p) = 1/9 (4 -5) X (40)(0 1) (m)(-3 6)(23)
    therefore (p) = 1/9 (45)(m) (18)
    p = 5
    m = 2

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  18. but torbo won't u have to find the determinent A and multipy it by c to get B

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  19. I still cannot understand what it is that you have to do in number one.

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  20. a singular matrix is when the determinant is equal to 0. is AD- BC=0 (a b)
    (c d)

    but i dont understant the first question either

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  21. i dont hthink it singular matrix could have an inverse bou i not 100% sure y not!

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  22. Wll "low rider" you have to find out if the matrix is singular and this is found by the

    major - minor = det

    once it is equal to 0, then the matrix is singular

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  23. Ok swanky thing i think i understand.

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  24. 14 ................6

    5x-3 ............8
    now to find the value of x that will make this matrix singular, the major - minor = zero. because a singular matrix has a determinant of zero.

    determinant = 14*8 - 6*(5x-3)= 0
    112 - (30x+18)= 0
    112 - 30x + 18 = 0
    112 + 18 = 30x
    130 = 30x
    x = 130/30 = 4.33

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