correct me if i'm wrong ok: when u have to integrate u add the powers and then divide by the sum of those the powers along with that the answer must hace +c
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ReplyDelete2. dy/dx = 6x + 1
ReplyDeleteintergral 6x + 1 dx
6x^2/2+ c
3. dy/dx = 2
ReplyDeleteintergral 2 = c
not sure about this could some one correct me if i am wrong
5. dy/dx = 7x^2 + 3x + 4
ReplyDeleteintergral 7x^2 + 3x + 4
= 7/3 x^3 + 3/2 x^2 + c
4. dy/dx = 8x^5 - 5x^3 + 4x
ReplyDeleteintergral 8x^5 - 5x^3 + 4x
= 8x^6 /6+ 5x^4/4 + 4x^2/2 + c
1. dy/dx = 5x^3 + 2x^2 + 5
ReplyDeleteintergral 5x^3 + 2x^2 + 5 dx
5x^4 /4 + 2x ^3/3 + c
I AM NOT SURE WHAT IF WHAT I AM DOING IS RIGHT
WHEN U HAVE 5 dx WHAT IS THE INTERGRAL OF IT??/
Hey "ken" ur mixing up urself,
ReplyDeleteFor question 2:
dy/dx = 6x + 1
the intergral = 3x^2 + 1x
Don't forget when you integrate that you have to include the constant: +C.
ReplyDeleteFor example, the integral of 3x^2 + 2x is:
x^3 + x^2 + c
correct me if i'm wrong ok:
ReplyDeletewhen u have to integrate u add the powers and then divide by the sum of those the powers along with that the answer must hace +c
ammm animechic i think u confuse me more than anything else " no offense" so i really not sure what u mean but if is anything like
ReplyDeletedy/dx = 5x^3 + 3x + 2
intergral = (5x^4)/4 + (3x^2)/2 + 2x/1 + c
then i suppose u on the right track
when integrating add the power by 1 and divide by the new power. and always + c
#5
ReplyDelete7/3x +3/2x^2+4x+c
Q1. dy/dx = 5x^3 + 2x^2 + 5
ReplyDeleteintegral = 5/4 x^4 + 2/3 x^3 +5x +c